b+2b+b^2+2b^2=3b^2+3b

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Solution for b+2b+b^2+2b^2=3b^2+3b equation: 



b+2b+b^2+2b^2=3b^2+3b

We move all terms to the left:

b+2b+b^2+2b^2-(3b^2+3b)=0

We add all the numbers together, and all the variables

3b^2+3b-(3b^2+3b)=0

We get rid of parentheses

3b^2-3b^2+3b-3b=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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